How many usable hosts are available in a /26 subnet?

Study for the Internet Protocol Version 4 Test. Use flashcards and multiple-choice questions, each with hints and explanations. Master the exam with confidence!

Multiple Choice

How many usable hosts are available in a /26 subnet?

Explanation:
In IPv4 subnetting, usable hosts = 2^(host bits) − 2 because the network address (all host bits zero) and the broadcast address (all host bits one) can’t be assigned to hosts. A /26 has 6 host bits (32 − 26 = 6), so total addresses = 2^6 = 64. Subtract the two reserved addresses and you get 62 usable hosts. The other options come from different subnet sizes: 64 would count all addresses without removing network/broadcast, 126 is for a /25, and 254 is for a /24.

In IPv4 subnetting, usable hosts = 2^(host bits) − 2 because the network address (all host bits zero) and the broadcast address (all host bits one) can’t be assigned to hosts. A /26 has 6 host bits (32 − 26 = 6), so total addresses = 2^6 = 64. Subtract the two reserved addresses and you get 62 usable hosts. The other options come from different subnet sizes: 64 would count all addresses without removing network/broadcast, 126 is for a /25, and 254 is for a /24.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy