How is the network address obtained when performing a bitwise AND operation between an IP address and a subnet mask?

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Multiple Choice

How is the network address obtained when performing a bitwise AND operation between an IP address and a subnet mask?

Explanation:
To find the network address, you use the subnet mask to separate the network portion from the host portion. The operation is a bitwise AND between the IP address and the subnet mask. Each bit is kept if the mask has a 1 there (network part) and cleared to 0 if the mask has a 0 there (host part). This zeros out the host bits and leaves the network bits intact, giving the network address. For example, with IP 192.168.10.77 and a 255.255.255.0 mask, the result is 192.168.10.0. That shows the network portion defined by the mask. Other operations aren’t used to derive the network address: OR would set more bits to 1, XOR would flip bits, and simply taking the IP address ignores the boundary defined by the mask.

To find the network address, you use the subnet mask to separate the network portion from the host portion. The operation is a bitwise AND between the IP address and the subnet mask. Each bit is kept if the mask has a 1 there (network part) and cleared to 0 if the mask has a 0 there (host part). This zeros out the host bits and leaves the network bits intact, giving the network address.

For example, with IP 192.168.10.77 and a 255.255.255.0 mask, the result is 192.168.10.0. That shows the network portion defined by the mask.

Other operations aren’t used to derive the network address: OR would set more bits to 1, XOR would flip bits, and simply taking the IP address ignores the boundary defined by the mask.

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