Given 172.16.0.0/14, what is the network address and the broadcast address?

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Multiple Choice

Given 172.16.0.0/14, what is the network address and the broadcast address?

Explanation:
When a CIDR of /14 is used, the subnet mask is 255.252.0.0. The network address comes from OR/AND operations that keep only the network bits: 172.16.0.0 AND 255.252.0.0 equals 172.16.0.0. The broadcast address uses the remaining host bits set to 1, which means OR-ing the network with the inverted mask (0.3.255.255). Doing that gives 172.16.0.0 OR 0.3.255.255 = 172.19.255.255. In this /14 block, the range spans from 172.16.0.0 to 172.19.255.255, so the network is 172.16.0.0 and the broadcast is 172.19.255.255.

When a CIDR of /14 is used, the subnet mask is 255.252.0.0. The network address comes from OR/AND operations that keep only the network bits: 172.16.0.0 AND 255.252.0.0 equals 172.16.0.0. The broadcast address uses the remaining host bits set to 1, which means OR-ing the network with the inverted mask (0.3.255.255). Doing that gives 172.16.0.0 OR 0.3.255.255 = 172.19.255.255. In this /14 block, the range spans from 172.16.0.0 to 172.19.255.255, so the network is 172.16.0.0 and the broadcast is 172.19.255.255.

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